Each group can be described in terms of one value. Calling this value N, basically the pendants in the group contain:
\[N, N, {N \over 2}, N, N, N, N, N, {N \over 2}, {N \over 2} \]
Where there are 9 rather than 10 pendant positions, one of the 5 consecutive positions with value N is non-existent. The values involved are:
\[N=24; ({N \over 2}=12); N=9; ({N \over 2}=4); N=5; ({N \over 2}=4); N=8; ({N \over 2}=4); N=4; ({N \over 2}=2); N=8; ({N \over 2}=4); N=4; ({N \over 2}=2); N=2; ({N \over 2}=1)\]
- Where N=8 (in groups 4, 6, 8), the value 8 is represented by a long knot of 4 immediately followed by a long knot of 4, rather than by a long knot of 8. Half of it is one long knot of 4 (in groups 4 and 8). By contrast, there is a double long knot of 2 in group 6. It is the distributive axiom, of course, that justifies the use of these 2 procedures to arrive at equivalent results. Namely, A = (A+A)/2 = (A/2) + (A/2)
- Since halving when only integers are used causes problems for odd values, it is important to note that 9/2 → 4.